Python *args and **kwargs MCQs – Multiple Choice Questions for Practice and Learning

Q1. What is the type of the variable that collects positional arguments when using `*args` in a Python function?

• 🟢 A. list
• 🔵 B. tuple
• 🟠 C. dict
• 🔴 D. set

Q2. What does `**kwargs` collect inside a Python function?

• 🟢 A. a list of positional arguments
• 🔵 B. a tuple of positional arguments
• 🟠 C. a dictionary of keyword arguments
• 🔴 D. a set of keyword arguments

Q3. Which symbol is used to define `*args` in a Python function?

• 🟢 A. *
• 🔵 B. **
• 🟠 C. &
• 🔴 D. #

Q4. Which symbol is used to define `**kwargs` in a Python function?

• 🟢 A. *
• 🔵 B. **
• 🟠 C. &
• 🔴 D. ##

Q1. What is the output of the following code?

def test(*args):
    return args
print(test(1, 2, 3))

• 🟢 A. [1, 2, 3]
• 🔵 B. (1, 2, 3)
• 🟠 C. {1: 2, 3: None}
• 🔴 D. Error

Q2. What is the output of the following code?

def test(**kwargs):
    return kwargs
print(test(a=1, b=2))

• 🟢 A. {'a': 1, 'b': 2}
• 🔵 B. [('a', 1), ('b', 2)]
• 🟠 C. ('a', 'b')
• 🔴 D. Error

Q3. Which of the following is TRUE about using both `*args` and `**kwargs` in the same function?

• 🟢 A. `*args` must come before `**kwargs`
• 🔵 B. `**kwargs` must come before `*args`
• 🟠 C. Order does not matter
• 🔴 D. They cannot be used together

Q4. What will the following function print?

def show(*args, **kwargs):
    print(args)
    print(kwargs)
show(1, 2, x=3, y=4)

• 🟢 A. (1, 2) and {'x': 3, 'y': 4}
• 🔵 B. [1, 2] and {'x': 3, 'y': 4}
• 🟠 C. (1, 2, 'x', 'y') and {}
• 🔴 D. () and {'1': 2, 'x': 3, 'y': 4}

Q5. What is the correct order of parameters in a Python function definition when using `*args` and `**kwargs`?

• 🟢 A. Regular arguments → *args → **kwargs
• 🔵 B. *args → Regular arguments → **kwargs
• 🟠 C. **kwargs → *args → Regular arguments
• 🔴 D. Any order is valid

Q1. What is the output of the following code?

def func(a, *args, **kwargs):
    print(a, args, kwargs)
func(1, 2, 3, x=4, y=5)

• 🟢 A. 1 (2, 3) {'x': 4, 'y': 5}
• 🔵 B. 1 [2, 3] {'x': 4, 'y': 5}
• 🟠 C. 1 (2, 3, 'x', 'y') {}
• 🔴 D. 1 () {'a': 1, 'x': 4, 'y': 5}

Q2. Which function definition is valid?

• 🟢 A. def func(*args, a, **kwargs): pass
• 🔵 B. def func(a, *args, **kwargs): pass
• 🟠 C. def func(**kwargs, *args, a): pass
• 🔴 D. def func(**kwargs, *args): pass

Q3. What will this code print?

def calc(*args):
    return sum(args)
print(calc(1, 2, 3, 4))

• 🟢 A. 10
• 🔵 B. (1, 2, 3, 4)
• 🟠 C. Error
• 🔴 D. [1, 2, 3, 4]

Q4. What will this code print?

def merge_dicts(**kwargs):
    return kwargs
print(merge_dicts(a=1, b=2, c=3))

• 🟢 A. {'a': 1, 'b': 2, 'c': 3}
• 🔵 B. ['a', 'b', 'c']
• 🟠 C. (1, 2, 3)
• 🔴 D. Error

Q5. What is the output of this code?

def show_args_kwargs(*args, **kwargs):
    return len(args) + len(kwargs)
print(show_args_kwargs(1,2,3,x=4,y=5))

• 🟢 A. 2
• 🔵 B. 3
• 🟠 C. 5
• 🔴 D. Error

Q6. What will happen if you pass duplicate keyword arguments to a function with `**kwargs`?

def test(**kwargs):
    print(kwargs)
# test(x=1, x=2)

• 🟢 A. The last value will overwrite the previous one
• 🔵 B. Both values will be stored
• 🟠 C. Python raises a SyntaxError
• 🔴 D. Python raises a RuntimeError